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"""
problem: count ocurrences of words
solution: tr ' ' '\n' | sort | uniq -c
e.g.: echo "When the going gets tough, the tough get going" | tr -s ' ' '\n' | sort | uniq -c | sort -bnr
heuristic: use a hashtable, a dictionary in python is close enough and will suffice
"""
import sys
counts = {}
for line in sys.stdin:
words = line.lower().split()
for word in words:
counts[word] = counts.get(word, 0) + 1
tupleList = sorted(counts.items(), key=lambda tup: tup[1], reverse=True)
for word, count in tupleList:
print(word, count)
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